1.
Triangle ABC is such that AB = 3cm, BC = 2 cm and CA = 2.5cm. ADEF is similar to
Triangle ABC. If EF = 4cm, find the perimeter of triangle of DEF.
Answers
ANSWER - 15 cm .
In ΔABC
In ΔABCAB = 3 cm
In ΔABCAB = 3 cmBC = 2 cm
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cm
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cm
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABC
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cm
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding triangles
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding trianglesSo, Let the perimeter of triangle DEF be x
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding trianglesSo, Let the perimeter of triangle DEF be xSo,4/2 = x/7.5
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding trianglesSo, Let the perimeter of triangle DEF be xSo,4/2 = x/7.54×7.5 = x
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding trianglesSo, Let the perimeter of triangle DEF be xSo,4/2 = x/7.54×7.5 = x 15=x
In ΔABCAB = 3 cmBC = 2 cmAC = 2.5 cmPerimeter of triangle = Sum of all sides = 3+2+2.5 = 7.5 cmTriangle DEF is similar to triangle ABCCorresponding side of EF in triangle ABC is BC = 2cmTheorem :The ratio of the sides of similar triangle is equal to the ratio of the perimeter of corresponding trianglesSo, Let the perimeter of triangle DEF be xSo,4/2 = x/7.54×7.5 = x 15=xHence perimeter of triangle DEF is 15