Question

1. Twice a number when decreased by 7 gives 45. Find the number
Thrice a number when increased by 5 gives 44. Find the number​

Answer 1

Answer:

Hey mate here is your answer

Step-by-step explanation:

1.the number is "26"

2.the number is" 13"

Answer 2

Twice a number when decreased by 7 gives 45. Find the number

Let a number be ' x '

Twice the number = 2x

According to the problem given,

Twice the number when decreased by 7 gives 45

=> 2x - 7 = 45

/* Add 7 both sides of the equation,we get

=> 2x - 7 + 7 = 45 + 7

=> 2x = 52

/* Divide both sides by 2, we get

=> x = 26

Therefore,

Required number = x = 26

Hence, 26 is the required number.

Thrice a number when increased by 5 gives 44. Find the number

3x +5=44

3x= 39

x=39/3

×=13

Hence, 13 is the required number