Question

1) Two blocks of mass 1kg and 2kg are connected by an in extensible
string which passes over a frictionless pulley as shown in figure.
calculate the acceleration of these blocks.
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Answer 1

Let the acceleration a act towards right so that the block of mass 2 kg goes down and that of 1 kg mass goes up along the plane due to this.

From the FBD of the block of mass 1 kg,

T - 5√3 = a → (1)

And from the FBD of the block of mass 2 kg,

10 - T = 2a → (2)

Now, adding (1) and (2),

10 - 5√3 = 3a

a = [5(2 - √3) / 3] m s^(-2)

a = 0.447 m s^(-2)

Answer 2

Answer:

I also dont know this question