1.
Two bodies have a mass ratio of 3:4 The
force applied on the bigger mass produces
an acceleration of 12 ms-2. What could be the
acceleration of the other body, if the same
force acts on it.
Answers
Answer:
The smaller mass accelerates at 16 m/s² when force equal to the amount applied on the bigger mass is applied on it.
Explanation:
Step 1 : Let the bigger mass be x.
The smaller mass will be = 3/4x
The formula for getting force is :
Force = Mass × acceleration
Step 2 : Calculate the force applied on the bigger mass.
Apply the formula above :
Force = x × 12 = 12x N
This same force is applied on the smaller mass.
We can get the acceleration of the smaller mass.
Step 3 : Calculate the acceleration of the smaller mass.
Mass = 3/4x
F = 12x
F = ma
12x = 3/4x × a
a = 12x × 4/3x
a = 16 m/s²
The acceleration of the smaller mass is given by :
= 16m/s
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Answer:
9 m/s-2
Explanation:
a = F/m , now as F is same,
a is inversely proportional to m. so,
a2/a1 = m1/m2
a2/12 = 3/4
a2 = 12*3/4
a2 = 9 m/s-2