Question

1. Two bodies have a mass ratio of 3:4 The
force applied on the bigger mass produces
an acceleration of 12 ms. What could be
the acceleration of the other body, if the
same force acts on it.
​

Answer 1

correct question :-

Two bodies have masses in the ratio 3 : 4. When a force is applied on the first body, it moves with an acceleration of 12 ${ms}^{ - 2}$How much acceleration will the same force produce in the other body?

➙ given :-

→ Ratio of two body massses = 3 : 4

→ acceleration = 12

➙ To find :-

• How much acceleration will the same force produce in the other body?

➙ formula required :-

$\orange{\bold{\boxed{F = mass × acceleration }}}$

➙ Solution :-

→ Let mass of Body A=3m

→ mass of body B=4m

→ Force applied =F

for Body A

$⟶$F=mass×accelration

$⟶$F=3m×12= 36 N

$⟶$for Body B

$⟶$F=mass×acceleration

$⟶$a=F/m

$⟶ \frac{36}{4}$

$⟶$9m/s²

hence, acceleration is 9 m/s²

Answer 2

Correct question :

Two bodies have masses in the ratio 3 : 4. When a force is applied on the first body, it moves with an acceleration of 12ms^-2.of the other body.How much acceleration will the same force produce in the other body?

Answer:

9m/s^2

Explanation:

Given :

Two bodies have a mass ratio 3 : 4.The force applied on the bigger mass produces an accelaration of 12 ms.

So,

$\sf{}Acceleration\ of\ first\ body, a_1=12ms^{-2}$

To Find :

$\sf{}Acceleration\ of\ 2nd\ body, a_2=\  ?^{-2}$

Solution :

Let the 1st body mass be 3m and 2nd be 4m.

We know the formula to find acceleration if Force and mass is given is :

$\sf{}Force=mass \times accelaration$

According to the question,it’s given that force is same in the cases.

So,let’s find the Force (of both first and second body), F :-

$\sf{} F = 3m \times 12$

$\sf{}\implies F =36N$

So,

$\sf{}Force\ of\ both\ objects\ = 36N$

$\sf{}Therefore,acceleration\ of\ second\ body= \dfrac{36}{4m}$

$\implies \sf{}9m/s^2$

$\sf{} Hence,acceleration\ of\ the\ other\ body\ is\ equal\ to\ 9m/s^2$