1. Two bodies of mass 3 kg and 4 kg are suspended at the ends of massless string passing over a
frictionless pulley. The acceleration of the system is (Take g = 9.8 m/s2)
2.A ball of mass 100 g and another ball of 120 g moves towards each other with speeds 6 m/s
and 5 m/s respectively. If they stick to each other colliding, what would be the velocity of the
combined mass after the collision?
Answers
Answered by
14
The mass of 3 kg goes up and mass of 4 kg comes down with an acceleration a. The tension in the string is uniform through out its length and is T.
T - 3 * g = 3 * a
4 * g - T = 4 * a
solving these, a = g/7 = 1.4 m/sec/sec and T = 24 * 1.4 Newtons
============================
Inelastic collision.
momentum is conserved after collision. There is a loss of energy in collision.
100 * 6 - 120 * 5 = (100+120) * v
v = 0 => the combined mass becomes stationary.
T - 3 * g = 3 * a
4 * g - T = 4 * a
solving these, a = g/7 = 1.4 m/sec/sec and T = 24 * 1.4 Newtons
============================
Inelastic collision.
momentum is conserved after collision. There is a loss of energy in collision.
100 * 6 - 120 * 5 = (100+120) * v
v = 0 => the combined mass becomes stationary.
iitjeepraveen:
cant understand
1st question. tension - weight of 3kg = mass 3kg * acceleration.... weight of 4 kg - tension in string = mass 4 kg * acceleration .. since the string is tight, does not expand on pulling, the acceleration of 3 kg and 4 kg are same.. entire string moves at same speed at every instant.
sum of initial momentum of both = 100 gm * (+6 m/s) + 120 gms * (-5 m/s) = 0. we use -5 m/s as it is in - x direction when 6 m/s is in +x direction. Hence on adding the two vectors (momentum), net momentum is zero.
there is energy loss = 1/2 m1 v1^2 + 1/2 m2 v2^2. due to inelastic collision. this energy is dissipated as sound, heat and light. also the bodies get deformed in shape. the energy is used in changing the shape of bodies.
Answered by
5
Answer:
☢️PLEASE MARK AS BRAINLIEST ☢️
Attachments:
Similar questions