Physics, asked by Shadetari6677, 11 months ago

1.Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is



(1) 116π (2) π (3) π3 (4) 35π

Answers

Answered by sakshi7860
0

3 is right

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Attachments:
Answered by atharvacjoshi
0

Answer:

phase =ϕ  

1

​  

 

sinϕ  

1

​  

=0.5A/A=0.5

=0.5

ϕ  

1

​  

=π/6

phase =ϕ  

2

​  

 

sinϕ  

2

​  

=−0.5 A/A

=−π/6

phase difference =ϕ  

1

​  

−ϕ  

2

​  

 

=  

3

π

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