1. Two charges
3× 10^-5
and
5×10
^5
are placed at a distance 10 cm from each other. Find the
value of electrostatic force acting between them.
Answer it fast and explain the calculation part
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Answered by
8
Explanation:
f=kq1q2/d^2
where the k is the constant and its value is 9×10^9
=9×10^9×3×10^-5×5×10^5/100×10^-4
=135×10^11
if ther is any mistake in calculations then sorry but you should remember the concept
Answered by
54
Question :-:
Given above ↑
Answer :-:
To find :-:
→ Electrostatic force (F)
Formula used :-
Explanation :-
Given that
→ distance between these forces ( r) is 10 cm = 0.1 m
apply the given formula
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