1. Two circles of radii 5 cm and 3 cm intersect at two points and the distance between
their centres is 4 cm. Find the length of the common chord,
2. If two equal chords of a circle intersect within the circle, prove that the segments of
one chord are equal to corresponding segments of the other chord,
3. If two equal chords of a circle intersect within the circle, prove that the line
joining the point of intersection to the centre makes equal angles with the
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Given parameters are:
OP = 5cm
OS = 4cm and
PS = 3cm
Also, PQ = 2PR
Now, suppose RS = x. The diagram for the same is shown below.
Ncert solutions class 9 chapter 10-10
Consider the ΔPOR,
OP2 = OR2+PR2
⇒ 52 = (4-x)2+PR2
⇒ 25 = 16+x2-8x+PR2
∴ PR2 = 9-x2+8x — (i)
Now consider ΔPRS,
PS2 = PR2+RS2
⇒ 32 = PR2+x2
∴ PR2 = 9-x2 — (ii)
By equating equation (i) and equation (ii) we get,
9 -x2+8x = 9-x2
⇒ 8x = 0
⇒ x = 0
Now, put the value of x in equation (i)
PR2 = 9-0
⇒ PR = 3cm
∴ The length of the cord i.e. PQ = 2PR
So, PQ = 2×3 = 6cm
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