Question

(1) Two dice are thrown, find the probability of the following event, Event D The sum on the upper most faces is at least 10. olution : Sample space (2.3), (2, 4); we - 5 - (1, 1), (1, 2); (2, 5), (2, 6); (3, 1), (3, 2); (1, 3) , (1, 4); (1, 5); (3, 3); (3, 4); (3, 5); (1, 6); (3, 6); (2, 1), (2, 2) , , , (4,1),(4,2),; (4, 3); (4, 4); (6, 3); (6, 4) , (4, 5) , (4, 6) , (6, 5) , (5, 1); (5, 2); (5, 3); (5, 4); (5, 5) , (6,6)); (5, 6); (6, 1), (6, 2); n(5) = Event D The sum on the upper most faces is at least 10, means the sum could be 10, 11 or 12. D n(D) Box P(D) - Write the formula Write the values Write the answer in simplified form(1) Two dice are thrown, find the probability of the following event, Event D The sum on the upper most faces is at least 10. olution : Sample space (2.3), (2, 4); we - 5 - (1, 1), (1, 2); (2, 5), (2, 6); (3, 1), (3, 2); (1, 3) , (1, 4); (1, 5); (3, 3); (3, 4); (3, 5); (1, 6); (3, 6); (2, 1), (2, 2) , , , (4,1),(4,2),; (4, 3); (4, 4); (6, 3); (6, 4) , (4, 5) , (4, 6) , (6, 5) , (5, 1); (5, 2); (5, 3); (5, 4); (5, 5) , (6,6)); (5, 6); (6, 1), (6, 2); n(5) = Event D The sum on the upper most faces is at least 10, means the sum could be 10, 11 or 12. D n(D) Box P(D) - Write the formula Write the values Write the answer in simplified form​

Answer 1

Answer:

Step-by-step explanation:

let one die be d1 and another be d2

sample space ={1;1,1;2,1;3,1;4,1;5,1;6,2;1,2;2,2;3,2;4,2;5,2;6,3;1,3;2,3;3,3;4,3;5,3;6,4;1,4;2,;4;3,4;4,4;5,4;6,5;1,5;2,5;3,5;4,5;5,;5;6,6;1,6;2,6;3,6;4,6;5,6;6}

n(s)=36

let A be the event of sun of the uppermost faces is at least 10

A={4;6,5;5,5;6,6;4,6;5,6;6}

n(A)=6

p(A)=n(A)/n(S)

=6/36

=1/6

the probability of the sum of the uppermost faces is at least 10 is 1/6

Hope it will help!