Question

(1) Two equal charges placed in air, separated by a
distance of 3 m, repel each other with a force of
0-19f. Calculate the magnitude of either of the
charges.​

Answer 1

Answer:

Explanation: I'm not clear about the force between the particles. However, you can get the answer by the formula,

F=Kq^2/r^2

Hope ur answer is cleared. And if u r satisfied with the answer mark me as brainliest.

Answer 2

Correct Question :-

Two equal charges placed in air, separated by a  distance of 3 m, repel each other with a force of 0.19 f.  Calculate the magnitude of either of the  charges.​

SoluTion :-

$\rm {d = 3 m}\\\\\\\rm {f = 0.19 \ f}\\\\\\\\\\\rm {f=\frac{kq^{2}}{r^{2}}}\\\\\\\rm {kq^{2}=0.19 \times 9}\\\\\\\rm {q^{2}=\frac{1.71}{9.0 \times 10^{9}}}\\\\\\\rm {q=\sqrt{0.19 \times 10^{-9}C} }$