Question

1. Two or more bulbs are said to be connected in series if the current flowing through one also flows
through the rest. The potential difference across the combination of bulbs connected in series is equal
to the sum of potential differences across the individual bulbs. So, The potential difference across each
bulb is directly proportional to its resistance. On the other hand, if bulbs are connected in parallel, the
potential difference across each bulb is same and the total current flowing through the parallel
combination is equal to the sum of currents passing through the individual bulbs. So, The current flow
through each bulb is inversely proportional to its resistance. Whether the bulbs are connected in series
or in parallel, the brightness of a bulb is more if the power consumed by it is more and vice-versa. The
power consumed by a bulb is given by, P = VI = IR = V?/R , where R is the resistance of the bulb, V
is the potential difference across the bulb and I is the flow of current through it.
If two tungsten bulbs with resistance R, and R, (R, > R, ) respectively are connected first in parallel
and then in series, in a lighting circuit across a battery ; then
1(a) Which bulb will glow more brightly when they are connected in parallel?
1(b) If the bulb of resistance R, burns out in series combination, how will the brightness produced change?
(1) Net brightness will increase.
(2) Net brightness will decrease.
(3) Net brightness will remain same.
(4) Net brightness will reduced to zero.​

Answer 1

Answer:

net brightness will reduced to zero