Question

1. Two parallel, metal plates are a distance 8.00 m apart. The electric field
between the plates is uniform, directed toward the right, and has a
magnitude of 4.00 N/C. If an ion of charge+2e is released at rest at the
left-hand plate, what is its kinetic energy when it reaches the right-hand
plate?
a. 4 eV.
b. 64 eV
c. 32 eV.
d. 16 eV​

Answer 1

Explanation:

We know E =

d

V

or, V=E.d =500×3×10

−3

=1500×10

−3

volt=1.5 volt

Answer 2

Answer:

b

Explanation:

As we know that

K.E = q delta V

and Delta V = Ed

so V=4×8 = 32V

so K.E = 2e ×32V

K.E=64eV

Hope it may be helpful