Question

(1)
Two particles A & B are projected from a building.
A is projected with speed 2V making an angle 30°
with horizontal & B with speed V making an angle
60° with horizontal. Which particle will hit the
ground earlier
V (B)
2V (A)
60°
30°
h
(1) Particle A
(2) Particle B
(3) Particle A & B will hit at same time.
(4) None of these​

Answer 1

Answer:

Particle B.

Explanation:

Vertical velocity equation

v(t)=−9.8t+sinθv0  

Particle will reach apex when v(t) = 0, if starting from ground level, then time to hit the ground is twice the time to reach apex.

Solve equation for v(t) = 0, then multiply by 2

T=2∗sinθv09.8  

Apply to both particles A and B

TA=2∗sin(30)(2V)9.8=V4.9  

TB=2∗sin(60)(V)9.8=.866V4.9  

TB<TA  

Therefore, particle B will hit the ground first.

Hope it helps...