Question

1. Two particles having equal mass and charges are placed at certain distance from
each other. The repulsive force between them is equal to double the weight of
one of the particles, then find the distance between them. ​

Answer 1

Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is given as follows.

The force between 2 charges q1 and q2 is given by the formula F = k (q1 ×q2) /r²--------------(1)

Where, q1 : Charge of object 1

q2 : Charge of object 2

r : Distance between the two objects

F : Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction

k : Coulomb Constant.

In this case, the distance between 2 charges is halved. So the new force becomes

Fnew = [k×(q1 ×q2)] / (r/2)²

= (4×k×q1×q2)/r²

= 4F. [ From eqn (1)]

Hence, the force between the charges becomes 4F.

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