1. Two pipes A and B can separately fill a cistern in 12 and 15 mins respectively
while a third pipe C can empty it in 10 mins. How long will it take to fill the
cistern if all the pipes are opened simultaneously?
(B) 10
(C) 12
(D) 15
(A) 9
Answers
Answered by
0
Step-by-step explanation:
Part filled in 5 min =5×(
12
1
+
15
1
)
=5×
60
9
=
4
3
Part emptied in 1 minute when all the pipes are opened =
6
1
−(
12
1
+
15
1
)=
60
1
.
Now,
60
1
part is emptied in 1 minute.
Therefore,
4
3
part will be emptied in 60×
4
3
=45 minutes.
Similar questions