Question

1. Two point charges +8q and -29 are located at x = 0 and x = L respectively. The point on x axis at which net electric field is zero due to these charges is : (a) 8L (b) 4L (c) 2 L (d) L .​

Answer 1

Explanation:

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Answer 2

GIVEN:

Two point charges $+8q and -2q$

$+8q$ is located at $x=0$;and$-2q$ is located at$x=L$

TO FIND:

The point on x axis at which net electric field is zero due to these charges

SOLUTION:

$E_{BO} =\frac{-1*8q}{4\pi E_{0}*a^{2} } i\\E_{BA}=\frac{1*2q}{4\pi E_{0}*(a+L)^{2} } i\\\\E_{BO}+E_{BA}=0\\\\\frac{-1*8q}{4\pi E_{0}*a^{2} } i=\frac{1*2q}{4\pi E_{0}*(a+L)^{2} } i\\\\\\\frac{2}{a}=\frac{1}{a+L}\\2a+2L=a\\2L=_a$

HENCE, At distance 2L from origin net electric field will be zero