Question

1. Two point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude of the electric force​

Answer 1

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Answer 2

The force between charges is 36 N.

Explanation:

Given that,

Charge 1, $q_1=8\ \mu C$

Charge 2, $q_2=10\ cm$

Distance between charges, d = 10 cm = 0.1 m

The electric force between charges is given by :

$F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\\\F=36\ N$

So, the force between charges is 36 N.

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