Question

1. Two relations R1, and R2 are defined as: R1 = {(x, y) €Z* Z:|x|+|y|=1} R2 = {(x, y) € N x N: 2xy÷xsquare+ysquare = 1}​

Answer 1

Answer:

Step-by-step explanation:

R={(x,y):x−yis an integer}

Now, for every x∈Z,(x,x)∈R as x−x=0 is an integer.

∴R is reflexive.

Now, for every x,y∈Z if (x,y)∈R, then x−y is an integer.

⇒−(x−y) is also an integer.

⇒(y−x) is an integer.

∴(y,x)∈R

⇒R is symmetric.

Now,

Let (x,y) and (y,z)∈R, where x,y,z∈Z.

⇒(x−y) and (y−z) are integers.

⇒x−z=(x−y)+(y−z) is an integer.

∴(x,z)∈R

∴R is transitive.

Hence, R is reflexive, symmetric, and transitive.