Question

1.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse
is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the
two ships is:
A. 173 m
B. 200 m
C. 273 m
D. 300 m
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Answer 1

Answer:

273 m

Explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

AB = 100m,∠ACB=30∘,

∠ADB=45∘

ABAC=tan=>AC=AB∗3–√=1003–√mABAD=tan=>AB=AD=100mCD=AC+AD=(1003–√+100)=100(3–√+1)=100∗2.7330∘=13–√45∘=1mmm=273m