1. Two substances A and B are present such that A = 4B and half life of A is 5 minute and that of B is 15 minute. If they start decaying at the same time following first order kinetics how much time will the concentration of both of them would be the same.
A, 15 minute b. 10 minute c. 5 minute d. 12 minute
Answers
Answered by
119
inital conc. Ao=4Bo
A conc. decs. as 4Bo=>2Bo=>Bo=>0.5Bo
B conc. decs. as Bo=>0.5Bo
thus, one half life of Bo=three half life of Ao
=15 mins
Answered by
27
Answer:15 minutes
Explanation:we know that
From. 4 B to 2B it will take 2 times
the time given
Similarly going from 4Bto 2B to B to
1B/2
It takes three times the half life time given so 3×5 =15min
Hope it helps
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