(1) Two tape A and B can together filla swimmmg pool in 15 days laps and are
kept open for 12 days and then tap B is closed It takes another 8 days for the pol
to be filled. How many days does each tap require to fill the pool (40 .24days)
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Solution :
Two tape A and B can together fill a swimmmg pool in 15 days taps.
=> 15A + 15B = 1 ...........(1)
A and B are kept open for 12 days and then tap B is closed It takes another 8 days for the pool to be filled.
=> 12A + 20B = 1 ...........(2)
Multiply both eq (1) and (2) by 12 and 15 respectively.
=> 180A + 180B = 12.........(3)
=> 300A + 180B = 15.........(4)
Solving (3) and (4), we get,
=> A = 1/40
•°• A would take 40 days to fill the pool.
Put the value of A in (2),
=> 1/2 + 12B = 1
=> 12B = 1/2
=> B = 1/24
•°• B would take 24 days to fill the pool.
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