Question

1. Two vibrating bodies have frequencies 512 Hz
and 510 Hz. Calculate the no. of beats​

Answer 1

$\sf \colorbox{gold}{{Given,}}$

The frequency of tuning fork,

$n _{f} =512Hz$

Beat frequency, x=4beats/sec

The beat frequency decreases to 2 beats per second, when the tension in the piano string is slightly increased.

We have to find the frequency of the piano,

$n_{p}$

$\sf \colorbox{lightpink}{{We have the equation,}}$

$n_{p}=n_{f} −x=512−4=508Hz$

When tension is increased the frequency also increased. As number of beats decreased, the frequency of string must be less than 512 Hz.

Hence the correct answer is 508 Hz.

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