Question

1/u-1/v graph in convex lens

Answer 1

❤❤HERE IS YOUR ANSWER ❤❤

1u+1v=1f where f is some constant property of the lens. Let y=1/u, and x=1/v. Then y=1/f − x, which is the equation of a straight line, gradient -1 and y-intercept 1/f. Setting y=0, we can get the x-intercept which it turns out is also 1/f

❤❤div❤❤