Question

1/under root 1+tan² theta​

Answer 1

Answer:

$\frac{1}{ \sqrt{1 + { \tan( \alpha ) }^{2} } } \\ = \frac{1}{ \sqrt{ { \sec( \alpha ) }^{2} } } \\ = \frac{1}{ \sec( \alpha ) } \\ = \cos( \alpha ) .$

note : I am using alpha in place of theta so don't get confused.

Step-by-step explanation:

formula used : sec²∅ - tan² = 1

Answer 2

This is your answer bro.

Formula is:

1+tan^2 =sec^2

If it helps pls mark it brainliest