Question

1/ under root 2+1/ under root 2/under root 2 + under root 2
$1 \div \sqrt{2} + 1 \div \sqrt{2 } \div \sqrt{2} + \sqrt{2 } =$
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Answer 1

Answer:

Step-by-step explanation:

$\frac {(\frac{1}{\sqrt{2} } + \frac{1}{\sqrt{2} } }{\sqrt{2} +\sqrt{2} }\\\\=\frac {\frac{2}{\sqrt{2} } }{\sqrt{2} } \\\\=\frac{\sqrt{2} }{2\sqrt{2} } \\\\\bf=\frac12$