Math, asked by narendermodi8848, 6 months ago

1 upon 1 + a power n minus M + 1 upon 1 + a power M minus n

Answers

Answered by parmanandmgrPrince
0

Step-by-step explanation:

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Answered by cmanu3286
0

Step-by-step explanation:

1+am−n1+1+an−m1

=\frac{1}{1+\frac{a^m}{a^n}}+\frac{1}{1+\frac{a^n}{a^m}}=1+anam1+1+aman1 (x^{a-b}=\frac{x^a}{x^b})(xa−b=xbxa)

=\frac{1}{\frac{a^n+a^m}{a^n}}+\frac{1}{\frac{a^m+a^n}{a^m}}=anan+am1+amam+an1

=\frac{a^n}{a^n+a^m}+\frac{a^m}{a^m+a^n}=an+aman+am+anam

=\frac{a^n+a^m}{a^n+a^m}=an+aman+am

=1=1

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