Question

1 upon 1 + sin theta + 1 upon 1 minus sin theta is equal to 2 sec square theta

Answer 1

Answer: Take the conjugate of each of the denominator and you’ll get a common denominator. Then, solve it until your reach your desired answer.

Step-by-step explanation:

(refer to attached image)

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Answer 2

$\frac{1}{1+\sin\theta}+ \frac{1}{1-\sin\theta}=2\sec^2\theta$ Proved.

Step-by-step explanation:

Consider the provided information.

$\frac{1}{1+\sin\theta}+ \frac{1}{1-\sin\theta}=2\sec^2\theta$

Consider the LHS.

$\frac{1}{1+\sin\theta}+ \frac{1}{1-\sin\theta}$

$=\frac{1-\sin\theta+1+\sin\theta}{(1+\sin\theta)(1-\sin\theta)}$

$=\frac{2}{1+\sin^2\theta}$

$=\frac{2}{\cos^2\theta}$

$=2\sec^2\theta$

LHS=RHS

Hence, proved

#Learn more

Cos theta/1-tan theta + sin theta/1-cot theta

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