1 upon 1+sinA+1upon1-sinA=2sec square A
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Hey!!!!
Good Afternoon
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To Prove : 1/(1 + sinA) + 1/(1 - sinA) = 2sec²A
Thus
LHS = 1/(1 + sinA) + 1/(1 - sinA)
=> (1 - sinA + 1 + sinA)/(1 - sinA)(1 + sinA)
=> 2/(1 - sin²A)
We know 1 - sin²A = cos²A
=> 2/cos²A
=> 2sec²A
=> RHS
Hence Proved
_____________
Hope this helps ✌️
Good Afternoon
_____________
To Prove : 1/(1 + sinA) + 1/(1 - sinA) = 2sec²A
Thus
LHS = 1/(1 + sinA) + 1/(1 - sinA)
=> (1 - sinA + 1 + sinA)/(1 - sinA)(1 + sinA)
=> 2/(1 - sin²A)
We know 1 - sin²A = cos²A
=> 2/cos²A
=> 2sec²A
=> RHS
Hence Proved
_____________
Hope this helps ✌️
CutiepieShruti:
thanks a lot
welcome
can you explain me the last step how sec square came
sec = 1/cos
oh understood not seen the solution properly
no problem
Answered by
1
this is yhe answer u need
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