Math, asked by poojaattry2005, 1 month ago

1 upon 2 + 2 and 1 upon 4 * 1 upon 8 ÷ 1 upon 9 - 1 upon 3​

Answers

Answered by adityak4m6le007
0

Step-by-step explanation:

 \frac{1}{2}  + 2 +  \frac{1}{4}  \times  \frac{1}{8}  \div  \frac{1}{9}  -  \frac{1}{3}   \\  =  \frac{1}{2}  + 2 +  \frac{1}{4}  \times  \frac{9}{8}  -  \frac{1}{3}  \\  =  \frac{1}{2}  + 2 +  \frac{9}{32}  -  \frac{1}{3 }  \\  =  \frac{16 + 64 + 9}{32}   -  \frac{1}{3}  \\  =  \frac{89}{32}  -  \frac{1}{3}  \\  =  \frac{267 - 32}{96}  \\  =  \frac{235}{96}

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