Question

1 upon 2 is a zero of polynomial 2 x cube + kx square + 11 x + X + 3 find the value of k
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Answer 1

Answer:

k = -35

Step-by-step explanation:

p(x) = 2x³ + kx² + x + 3

1/2 is a zero of p(x)

then x = 1/2

puy x in p(x)

p(1/2) = 2(1/2)³ + k(1/2)² + (11)1/2 + 3

2(1/8) + k(1/4) + 11/2 + 3

1/4 + k/4 + 1/2 + 3

. (1 + k + 22 + 12)/4 = 0

35 + k = 0

k = -35