1 upon 2-under root 5
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©1 / 2 - √5
by rationalizing denominator of given fraction , we get
= 1 /( 2 - √5 ) × ( 2 + √5 ) / ( 2 + √5 )
use identity :- a^2 - b ^2 = ( a - b )( a + b ) in denominator , here a = 2 ,and b = √5
= 2 + √5 / ( 2) ^2 - ( √5 )^2
= 2 + √5 / 4 - 5
= - ( 2 + √5 )
by rationalizing denominator of given fraction , we get
= 1 /( 2 - √5 ) × ( 2 + √5 ) / ( 2 + √5 )
use identity :- a^2 - b ^2 = ( a - b )( a + b ) in denominator , here a = 2 ,and b = √5
= 2 + √5 / ( 2) ^2 - ( √5 )^2
= 2 + √5 / 4 - 5
= - ( 2 + √5 )
JayeshPargi:
can you solve on a paper and send the Photo
it already solved
you are brilliant :
i thought ,you called me to explain it more , thats why i explained it in detail. you could see ,it hope it helps
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how you did like I dont know how the valuse came there... Explain completely please
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