1 upon 2 whole cube x 3 upon 2 square x 2 whole cube
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Answer:
The formula of (a-b) is
(a−b)3 = (a3−3a2b+3ab2−b3)
Here is the method to derive it
For this you have to derive it according to the algebraic rules
Firstly take it as LHS= (a−b)3
Just open the cube form
(a−b)3 = (a−b)(a−b)(a−b)
Multiply any two terms of above equation
(a−b)3 = [a(a−b)−b(a−b)](a−b)
(a−b)3 = (a2−ab−ba−b2)(a−b)
As we know in algebra ab=ba
So that
(a−b)3 = (a2−ab−ab+b2)(a−b)
(a−b)3 = (a2−2ab+b2)(a−b)
Again multiply remaining terms
(a−b)3 = [a2(a−b)−2ab(a−b)+b2(a−b)]
(a−b)3 = (a3−a2b−2a2b+2ab2+ab2−b3)
Add similar terms
(a−b)3 = (a3−3a2b+3ab2−b3)
Now we have got the formula of cube form of (a-b)
(a−b)3 = (a3−3a2b+3ab2−b3)
Step-by-step explanation:
hope its help you
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