Question

1 upon 3 X + Y + 1 upon 3 x minus Y is equal to 3 upon 4

Answer 1

answer is x=1 and y=1. I hope you will understood

Answer 2

Answer:

The value of x=1 and y=1

Step-by-step explanation:

Given two equations

$\frac{1}{3x+y}+\frac{1}{3x-y}=\frac{3}{4}$

$\frac{1}{2(3x+y)}-\frac{1}{2(3x-y)}=\frac{-1}{8}$

We have to solve the equations for x and y

$\frac{1}{3x+y}+\frac{1}{3x-y}=\frac{3}{4}$  →  (1)

$\frac{1}{2(3x+y)}-\frac{1}{2(3x-y)}=\frac{-1}{8}$

⇒ $\frac{1}{(3x+y)}-\frac{1}{(3x-y)}=\frac{-1}{4}$  →  (2)

Adding (1) and (2),we get 3x+y=4

Subtracting (1) and (2), we get 3x-y=2

Solving above two we get

3x+y+3x-y=6 ⇒ 6x=6 ⇒ x=1

& 3x+y-3x+y=2 ⇒ 2y=2 ⇒ y=1