Question

1 upon √7-√5 rationalize denominator​

Answer 1

Answer:

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Answer 2

Answer:

$\\\frac{\sqrt{7}+\sqrt{5} }{2}$

Step-by-step explanation:

$\frac{1}{\sqrt{7}-\sqrt{5} \\}\\\\\frac{1}{\sqrt{7}-\sqrt{5} \\} *\frac{\sqrt{7}+\sqrt{5} }{\sqrt{7}+\sqrt{5}} \\\\\frac{\sqrt{7}+\sqrt{5} }{2}$

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