Question

1 upon √7 - √5 rationalize the denominator​

Answer 1

Answer:

the answer for this is root7+root5/2

Step-by-step explanation:

1/root7-root5

multiply and divide the conjugate root7+root5

1/root7-root5*root7+root5/root7+root5

we get root 7+root5/7-5

answer will be

root7+root5/2

and here the denominator is rationalized

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Answer 2

Question:

${Rationalize \: the \: denominator \: of} \\ \frac{1}{ \sqrt{7} - \sqrt{5} } </p><p>$

Solution:

$\frac{1}{ \sqrt{7} - \sqrt{5} } \frac{ \: \:\times \sqrt{7} + \sqrt{5} }{ \: \times \sqrt{7} + \sqrt{5} } \\ \\ = \frac{ \sqrt{7} + \sqrt{5} }{( \sqrt{7} ) {}^{2} - ( \sqrt{5}) {}^{2} } \: \\ ({ using \: \: ({a}^{2} - {b}^{2}) = (a + b)(a - b)) } \\ \\ = \frac{ \sqrt{7} + \sqrt{5} }{7 - 5} \\ \\ = \frac{ \sqrt{7} + \sqrt{5} }{2}$

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