Question

1 .Use remainder theorem to find the remainder when p(x) is divided by q(x) in the
following
a) p (x) = 2x^2 - 5x + 7 p(x) = x-1
b) p (x) = x^9 - 5x + 1

Answer 1

Hello friends!!

Here is your answer :

Given,

( a) p (x) = 2x² - 5x + 7

q ( x) = x - 1

Put q (x) = 0

x - 1 = 0

x = 1

p (1) = 2(1)² - 5(1) + 7

= 2 - 5 + 7

= 9 - 5

= 4

Remainder = 4.

________________

( b) p(x) = x^9 - 5x + 1

q (x) = x + 1

Put q (x) = 0

x + 1 = 0

x = - 1

p (x) = (-1)^9 - 5(-1) + 1

= - 1 + 5 + 1

= 6 - 1

= 5

Remainder = 5



Hope it helps you..

Answer 2

Hey!

_____________________________________________________________________________________________

Q 1. p(x) = 2x² - 5x + 7

_______________________________

Solution :-

=> x - 1 = 0

=> x = 1

_______________________________

•Remainder theoram :-

•Put value of x :-

_______________________________

=>p(1) = 2(1)² - 5(1) + 7

=> 2 - 5 + 7

=> 9 - 5

=> 4

______________________________________________________________

Q 2. p(x) = x^9 - 5x + 1
_______________________________

Solution

x + 1 = 0

x = -1

_______________________________

•Put value of x :-

•Remainder theoram :-

_______________________________

p(x) = (-1)^9 - 5(-1) + 1

= -1 + 5 + 1

= 6 - 1

= 5

Remainder = 5

_____________________________________________________________________________________________

Regards :)

Cybary

Be Brainly