Question

1. Using appropriate properties find​

Answer 1

Using BODMAS,

$\huge\boxed{ \left( - \frac{3}{7} \right) - \frac{1}{6} \times \frac{3}{2} + \frac{1}{14} \times \frac{2}{5} \: \: = \: \: - \frac{13}{20} }$

Answer:

We have,

$\LARGE{ \left( - \frac{3}{7} \right) - \frac{1}{6} \times \frac{3}{2} + \frac{1}{14} \times \frac{2}{5} }$

$\LARGE{ = \left( - \frac{3}{7} \right) - \left( \frac{1}{6} \times \frac{3}{2} \right) + \left( \frac{1}{14} \times \frac{2}{5} \right) }$

$\LARGE{ = \left( - \frac{3}{7} \right) - \left( \frac{1}{_3 \cancel{6} } \times \frac{ \cancel{3} \: {}^{1} }{2} \right) + \left( \frac{1}{_7 \: \cancel{14} } \times \frac{ \cancel{2} \: {}^{1} }{5} \right) }$

$\LARGE{ = \left( - \frac{3}{7} \right) - \left( \frac{1}{4} \right) + \left( \frac{1}{35} \right) }$

$\LARGE{ = - \frac{3}{7} - \frac{1}{4} + \frac{1}{35} }$

$\LARGE{ = \frac{ - 60 - 35 + 4}{140} }$———-——[ taking 140 as LCM ]

$\LARGE{ = - \frac{91}{140} }$

$\LARGE{ = - \frac{13 \times 7}{20 \times 7} }$

$\LARGE{ = - \frac{13 \times \cancel{7} }{20 \times \cancel{7} } }$

$\LARGE{ = - \frac{13 \times 1}{20 \times 1} }$

$\LARGE{ = - \frac{13}{20} }$