Math, asked by sonusharma138, 7 months ago

1. Using identities and factorisation, divide (16c^4a^2-12ab-9b^2) by (2a+3b+4c)
2. Factorise (ax+by)^2-(bx+ay)^2​

Answers

Answered by amitpad0007
10

Answer:

1. -4a^2-12ab-9b^2+16c^2

-[(2a)^2+2.2a.3b+(3b)^2]+16c^2

-(2a+3b)^2+16c^2

16c^2-(2a+3b)^2

(4c)^2-(2a+3b)^2

we know that a^2-b^2

(4c+2a+3b)(4c-2a-3b)by 2a+3b+4c

(4c-2a-3b)answer.

Answered by arjithks2013
0

Answer:2c^4a^1 -4ab-9b^2Step-by-step explanation:16c^4a^2-12ab-9b^2/12a+3b+4c simplify this you will get your answer and my answer is this please check this with your answer

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