Question

1. Using proper identities factorise the following:
1-64x3-12x + 48x?
25a? ​

Answer 1

we can use the identity

(a-b)³ = a³ - 3a²b + 3ab² - b³.

here , a =1 , b = 4x.

(1)³ - 3 (1)² × 4x + 3 (1) (4x)² - (4x)³

= 1 - 3 × (4x) + 3 ×16x² - 64x³ (now multiply these terms and get the answer.)

1 - 12x + 48x² - 64 x³

it can be written as 1 - 64x³ -12x +48x² .

The answer is verified 1-64x³ - 12x +48x².