Question

1). using remainder therom find the value of k ,if dividing 2X3+3X2-KX+5 by (X-2) leaves the remainder i......

2).Mr. Britto deposits a certain sum of money each month in a RDA of bank .If the rate of interest is 8% p.a and Mr Britto gets ₹8088 from the bank after 3yrs .Find the value of his monthly installment.

Answer 1

Answerof 1st question

Answer 2

remainder theorem,

a = bq + t

so, 2x³ +3x² -kx +5 is divided by (x -2) and remainder 1

so, 2x³ + 3x² -kx + 5-1 is divided by (x -2) then, remainder 0
so,( x -2) is factor of above,
hence, x = 2 is zeros of above expression

so, put x = 2 in expression .

2(2)³ +3(2)²-2k +4 = 0
16 + 12+ 4 = 2k
K = 16

2) use formula,
SI = P × R × T/100
(8088 - P ) = P × 8 × 3/100

8088 - P = 0.24 P

8088 = 1.24 P

P = 8088/1.24
= 6522 .58 Rs

hence , monthly installment = 6522.58/36 = 181 Rs