Math, asked by kapilmauryaji77, 2 months ago

1.using suitable identity solve these:

(i)(2y+5) (2y-5)

(ii) (2y+3) (2y+3)

(iii) (2a-7) (2a-7)

(iv) (2x+y) (2x+y)​

Answers

Answered by nitas1985123
1

Answer:

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Answered by venkatmanoj1
0

Answer: The identidies are

(i) (a+b)(a-b)=(a-b)²

(ii)(a+b)(a+b)=(a+b)²

(iii)(a-b)(a-b)= (a+b)²

(iv)(a+b)(a+b)=(a+b)²

Step-by-step explanation: Because

+×-=-

+×+=+

-×-=+

+×+=+

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