1.using suitable identity solve these:
(i)(2y+5) (2y-5)
(ii) (2y+3) (2y+3)
(iii) (2a-7) (2a-7)
(iv) (2x+y) (2x+y)
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Answer: The identidies are
(i) (a+b)(a-b)=(a-b)²
(ii)(a+b)(a+b)=(a+b)²
(iii)(a-b)(a-b)= (a+b)²
(iv)(a+b)(a+b)=(a+b)²
Step-by-step explanation: Because
+×-=-
+×+=+
-×-=+
+×+=+
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