Question

1) Using the data given at the end of the chapter, find first v/r for the moon where 'V' is the velocity and 'r' is the distance from the earth. Then find the acceleration due to gravity at the distance of the moon using the inverse square law. Take acceleration due to gravity near the earth of 9.8 m/s2​

Answer 1

Answer:

Solution



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Here, g=9.81m s−2

R=6.37×106m, r=3.84×108m

T=27.3days =27.3×24×60×60s

∴Me=GgRe2=6.67×10−119.81×(6.37×106)2=5.97×1024kg

Alternative method: Since the gravitational pull provides the required centripetal force, so

mr(2π/T2)=GMem/r2 or Me=GT24π2r3

=6.67×10−11×(27.3×24×60×60)24×(22/7)2×(3.84×108)3

=6.02×

Explanation:

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