Question

1) using the given values, verify the formulae for squares of binomial
i) a = 11, b = 3

Answer 1

Answer:

a² + b²=11²+3²=121+9=300

Answer 2

Step-by-step explanation:

(a + b)2 = (11 + 3)2 = 142 = 196 a2 + 2ab + b2 = 112 + 2 x 11 x 3 + 32 = 121 + 66 + 9 = 196 ∴(a + b)2 = a2 + 2ab + b2 (a – b)2 = (11 – 3)2 = 82 = 64 a2 – 2ab + b2 = 112 – 2 x 11 x 3 + 32 = 121 – 66 + 9 = 64