Question

1. Using the measures of the angles given in the figure alongside, find the measures of the remaining three angles.​

Answer 1

Answer:

angle DOE=8y )

angle AOF=6y ) Vetically opposite angles

Angle BOC=4y )

8y+6y+4y=180

18y=180

y=10

DOE=80

AOF=60

BOC=40

Answer 2

Answer:

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EOD=8y or 80°

BOC=4y or 40°

AOF=6y or 60°

Step-by-step explanation:

angle EOD=angle AOB. (vertically opposite angle)

therefore angle EOD=8y

as FC is a straight line

therefore angle FOE+EOD+DOC=180°

therefore 4y+8y+6y=180°

18y=180°

y=10°

similarly AD is a straight line

let angle BOC be ay

therefore 8y+6y+ay=180°

80+60+ay=180°

ay=40°

a=40/10 (as y=10°)

a=4

therefore angle BOC=4y

similarly BE is a straight line

let angle AOF be by

therefore 8y+4y+by=180°

80+40+by=180°

by=60°

b=60/10 (as y=10°)

b=6

therefore angle AOF=6y