1. Verify the following system of linear equations is diagonally dominant or not?
x+2y+z=4, 3x+4y+87=13 and x+3y+z=5
Answers
Given : x+2y+z=4,3x+4y+8z=13,x+3y+z=5
To Find : system of linear equations is diagonally dominant or not
Solution:
x + 2y + z = 4
3x + 4y + 8z = 13
x + 3y + z = 5
diagonally dominant :
If in every row of the matrix, the magnitude of the diagonal entry is larger than or equal to the sum of the magnitudes of all the other (non-diagonal) entries in that row.
aii ≥ ∑aij i≠j
a11 ≥ a12 + a13
a11 = 1 , a12 + a13 = 2 + 1 = 3
Hence a11 < a12 + a13 so Matrix is not Diagonal dominant
a22 ≥ a21 + a23
a22 = 4 , a21 + a23 = 3 + 8 = 11
a22 < a21 + a23
a33 ≥ a31 + a32
a33 = 1 , a31 + a32 = 1 + 3 = 4
a33 < a31 + a32
Hence system of linear equations is not diagonally dominant
Learn More:
diagonally dominant or not
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Answer:
done
Step-by-step explanation:
Given : x+2y+z=4,3x+4y+8z=13,x+3y+z=5
To Find : system of linear equations is diagonally dominant or not
Solution:
x + 2y + z = 4
3x + 4y + 8z = 13
x + 3y + z = 5
\begin{gathered}[\begin{array}{ccc}1&2&1\\3&4&8\\1&3&1\end{array}]\end{gathered}
[
1
3
1
2
4
3
1
8
1
]
diagonally dominant :
If in every row of the matrix, the magnitude of the diagonal entry is larger than or equal to the sum of the magnitudes of all the other (non-diagonal) entries in that row.
aii ≥ ∑aij i≠j
a11 ≥ a12 + a13
a11 = 1 , a12 + a13 = 2 + 1 = 3
Hence a11 < a12 + a13 so Matrix is not Diagonal dominant
a22 ≥ a21 + a23
a22 = 4 , a21 + a23 = 3 + 8 = 11
a22 < a21 + a23
a33 ≥ a31 + a32
a33 = 1 , a31 + a32 = 1 + 3 = 4
a33 < a31 + a32
Hence system of linear equations is not diagonally dominant
Learn More:
diagonally dominant or not
https://brainly.in/question/