Question

1
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(VI) 0.00
12. Which of the following numbers are perfect cubes ?
64, 125, 243, 729, 1331, 864, 4096, 74088
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Answer 1

$\sqrt[3]{64} = 4 \\ \sqrt[3]{125} = 5 \\ \sqrt[3]{243} = 7 \\ \sqrt[3]{729} = 9 \\ \ \sqrt[3]{1331} = 11 \\ \sqrt[3]{864} = 8 \\ \sqrt[3]{4096} = 16 \\ \sqrt[3]{74088} = 42$

Answer 2

Answer:

resolve into prime factors and see if you can group these factors into triplets of equal numbers