Question

(1+w-w^2)^3 - ( 1-w+w^2)^3 = 0
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Answer 1

Answer: (1+ω)  3 −(1+ω  2  )  3  

=(1+ω−1−ω  2  )

[(1+ω)  

2 +(1+ω)(1+ω  2  )+(1+ω  2  )  2  ]

=(ω−ω  2  )

[1+ω  2  +2ω+1+ω  2  +ω+ω  3  +1+ω  4  +2ω  2  ]

=(ω−ω  2  )

[4+4ω+4ω  2  ]

=(ω−ω  2  )×0

=0

Step-by-step explanation: Mark me as brainliest i am near to ace badge