Math, asked by as4263445, 10 months ago

1. water displaced out of the cylindrical vessel.
2.water left in the cylindrical vessel.​

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Answers

Answered by sonia007
1

Answer:

your answers are:

1.water displaced out=77cm^3

2.water left=5.5cm^3

Step-by-step explanation:

AS WE KNOW

volume of cylinder= total volume

vol.=πr^2h

22/7×5×5×10.5

we get total volume as 82.5cm^3

NOW WE WILL FIND THE VOLUME OF CONE

vol.=1/3πr^2h

1/3×22/6×3.5×3.5×6

now we get the cone value as 77cm^3

NOW HERE COMES THE ANSWER OF THE 1 QUESTION

the water displaced=to the volume of cone

(the Archimedes principle)

so the ans.1=77cm^3

NOW HERE COMES THE SECOND ANS.

that is the water left

•total vol -displaced vol.

82.5-77

=5.5cm^3

.

.

.hope it helps

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