Question

1.we're you able to connect the call outs to its right factor?

2.was it easy for you to find the factors of the given polynomials? If did yes hoow did you do it? ​

Answer 1

 In this section we look at factoring polynomials a topic that will appear in ... So, if you can't factor the polynomial then you won't be able to even start ... For instance, here are a variety of ways to factor 12.

I hope my answer is help you

Answer 2

All the polynomials above have used algebraic formulas to solve them

GIVEN:- factors of the given polynomials

TO FIND:- How are factorizations done

SOLUTION:-

1) Yes I was able to connect the call-outs to the right factor

2) Yes, it was easy for me to find the factors of the given polynomials

1. In the first polynomial 2ab is taken as a common factor
2. In the second polynomial a² - b² formula is used which is (a+b) (a-b)
3. In the third polynomial (a-b)² formula is used which is a²-2ab+b²
4. In the fourth polynomial 6ab is taken as the common factor by taking LCM
5. In the fifth polynomial mid-term breaking rule is used and the second factor is kept in the form of a²-ab+b².

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